Cement content 5 to 10%. Similar to the
This section discusses the various methods currently in use to design composite pavement
The 1993 AASHTO Guide for Design of Pavement Structures can be used to design two
cement) base and (2) a rehabilitated PCC pavement using the section in the guide for the design
of AC overlays of PCC (both jointed plain concrete pavement [JPCP] and continuously
7
A study performed by Richardson (1996) provides a general equation that could be used
to
determine the modulus, E
c
, of various cemented materials (e.g., soil cement, cement-treated
bases, cement-stabilized soils) and with that, compute the layer coefficient a
2
. Once the
cemented material coefficient and all other
needed parameters are obtained, the composite
structure can be designed.
( )
0.7784
c
u
E
34.367 2006.8 q
= −
+
(2)
( )
2
c
a
2.7170 0.49711 Log E
= −
+
×
(3)
where
E
c
= chord modulus (MPa)
q
u
= unconfined compressive strength (MPa).
The second alternative for using the AASHTO 1993 guide is based on the procedure for
designing the rehabilitation of PCC pavements with an AC overlay. In this case, the first step is
to design a conventional PCC pavement, in other words, compute the thickness to satisfy the
future traffic demand, D
f
. Once the slab thickness has been obtained, it could be assumed that
placing an AC layer with a thickness of approximately 50 mm (2 in) would allow for the
decrease of 25 mm (1 in) of PCC layer. This is because the guide’s “AC Overlay of PCC
Pavement” procedure indicates that the required thickness, D
OL
, of an AC overlay of PCC is
calculated using the following equation:
(
)
OL
f
eff
D
A D
D
=
−
(4)
Where
A = factor to convert PCC thickness deficiency to AC overlay thickness
D
f
= slab thickness to carry future traffic (in)
D
eff
= effective thickness of existing slab (in).
Therefore, two assumptions are made. First, in a new composite pavement design, D
eff
is
equal to D
f
because it is appropriate to assume that a newly constructed PCCP would not have
any distress, thus none of the adjustment factors shown in Equation 5 would be applicable.
eff
jc
dur
fat
D
F
F
F
D
=
×
×
×
(5)
Where
D = original slab thickness (this would be equal to the thickness of the rigid base)
F
jc
, F
dur
, F
fat
= adjustment
factors for joints and cracks, durability, and fatigue = 1.
The second assumption involves the A factor from Equation 4. According to the guide,
the A factor is computed using the following equation:
8
(
)
(
)
2
f
eff
f
eff
A 2.2233 0.0099 D
D
0.1534 D
D
=
+
−
−
−
(6)
Assuming that D
f
= D
eff
, a conservative value of A = 2.2233 would be obtained. Lower
A values, and consequently HMA thicknesses, may be obtained if using the actual D
f
and D
eff
values. For example, a 150 mm (6 in) HMA layer is required to substitute an HMA thickness of
87.5 mm (3.5 in) of PCCP in the example considered in this report. Once the overlay thickness
is computed, it is typically rounded to the nearest 0.5 in.
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