Exercise 3.4. If are real numbers, prove that
When does equality hold?
Solution:
Let
By Minkowski's inequality (for ) we have
Hence the LHS of the desired inequality is not greater than , while the RHS is equal to . Now it is sufficient to prove that
The last inequality can be reduced to the trivial . The equality in the initial inequality holds if and only if for some and
Exercise 3.5. If are real number, prove that
Solution:
We will prove first by induction that:
The case is a consequence of the Minkowski's inequality for and sequences . If the inequality holds for some , then
The equality holds if and only if for some fixed real number and real numbers . Applying this to the sequences we get
The equality holds if and only if .
Exercise 3.6. Solve the equation
Solution:
Applying Minkowski's inequality, we have
Equality holds if and only if .
Hence the root of the given equation is . These inequalities in most cases have as variables the lengths of the sides of a given triangle; there are also inequalities in which appear other elements of the triangle, such as lengths of heights, lengths of medians, lengths of the bisectors, angles, etc.
CHAPTER 4: GEOMETRIC ( TRIANGLE ) INEQUALITY
First we will introduce some standard notation which will be used in this section:
-lengths of the altitudes drawn to the sides , respectively.
-lengths of the medians drawn to the sides , respectively.
-lengths of the bisectors of the angles , respectively.
-area, -semi-perimeter, - circumradius, -inradius.
Furthermore we will give relations between the lengths of medians and lengths of the bisectors of the angles with the sides of a given triangle.
Namely we have
and
We can rewrite the last three identities in the following form
Also we note that the following properties are true, and we'll present them without proof. (The first inequality follows by using geometric formulas and mean inequalities, and the second inequality immediately follows, for instance, according to Leibniz's theorem.)
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