Birmingham-mumbai

yield 'data: {}\n\n.format(

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Sherwin John Tragura - Building Python Microservices with FastAPI Build secure, scalable, and structured Python microservices from design concepts to infrastructure-Packt Publishing - ebooks Account

StreamingResponse(filtered_image, media_type="image/png")
@router.get("/restaurant/upload/video")

yield 'data: {}\n\n.format(
json.dumps(jsonable_encoder(q),
cls=MyJSONEncoder))
await asyncio.sleep(1)
return
StreamingResponse(print_questions(),
media_type="text/event-stream")
• Services that render images can also use the
StreamingResponse
type. The following
logo_upload_png()
service uploads any
JPEG
or
PNG
file and renders it in the browser:
@router.post("/restaurant/upload/logo")
async def logo_upload_png(
logo: UploadFile = File(...)
):
original_image = Image.open(logo.file)
original_image =
original_image.filter(ImageFilter.SHARPEN)
filtered_image = BytesIO()
if logo.content_type == "image/png":
original_image.save(filtered_image, "PNG")
filtered_image.seek(0)
return
StreamingResponse(filtered_image,
media_type="image/png")
elif logo.content_type == "image/jpeg":
original_image.save(filtered_image, "JPEG")
filtered_image.seek(0)
return
StreamingResponse(filtered_image,

Utilizing Other Advanced Features
304
media_type="image/jpeg")
• The
StreamingResponse
type is also effective in rendering videos in various formats such
as
MP4
. The following service reads a file inside the application named
sample.mp4
and
publishes it to the browser:
@router.get("/restaurant/upload/video")
def video_presentation():
file_path = os.getcwd() + '\\files\\sample.mp4'
def load_file():
with open(file_path, mode="rb") as video_file:
yield from video_file
return
StreamingResponse(load_file(),
media_type="video/mp4")
• If the service wants to publish a simple HTML markup page without making references to static
CSS or JavaScript files, then
HTMLResponse
is the right choice. The following service renders
an HTML page with a Bootstrap framework provided by some CDN libraries:

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