Arifmetik progressiyaning n-hadi formulasi: ; Hadning nomerini topish
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| 35. ni hisoblang.
36. 1 dan 75 gacha bo’lgan natural sonlardan kvadratini 3 ga bo’lganda 1 qoldiq qoladigan sonlar yig’indisini toping. 37. Arifmetik progressiya uchun quyidagi formulalardan qaysilari to’g’ri? 1) ; 2) ;3) 38. y; 3y+5; 5y+10;... arifmetik progressiyaning dastlabki 8 ta hadi yig’indisi 396 ga teng. y ni toping. 39 ketma-ketlikning dastlabki 10 ta hadi yig’indisi 255 ga teng. a ning qiymatini toping. 40. Arifmetik progressiyaning dastlabki sakkizta hadi yig’indisi 32 ga, dastlabki 20 ta hadining yig’indisi 200 ga teng. Progressiyaning dastlabki 28 ta hadining yig’indisini toping. 41. Arifmetik progressiyaning dastlabki uchta hadi yig’indisi 66 ga, ikkinchi va uchinchi hadlarining ko’paytmasi 528 ga teng. Progressiyaning birinchi hadini toping. 42. Arifmetik progressiyaning oltinchi hadi 10 ga, dastlabki 16 ta hadining yig’indisi 200 ga teng. Bu progressiyaning 12-hadini toping. 43. Arifmetik progressiyaning dastlabki 16 ta hadi yig’indisi 840 ga, oxirgi 16-hadi 105 ga teng. Shu progressiyaning ayirmasini toping. 44. 25 ta ketma-ket natural sonning yig’indisi 1000 ga teng. bu sonlarning kichigi nechaga teng bo’ladi? 45. Sakkizta ketma-ket kelgan sonlarning yig’indisi 700 ga teng. Shu sonlardan eng kichigini toping. 46. Ketma-ket kelgan oltita natural sonning yig’indisi 435 ga teng. shu sonlarning eng kichigini toping. 47. tenglamaning ildizi 10 dan nechta kam? 48. Tenglikni qanoatlantiruvchi natural son N ni toping: 49. ni soddalashtiring. 50. ni soddalashtiring. 51. O’zidan oldingi barcha natural sonlar yig’indisining 1/10 qismiga teng bo’lgan natural sonni toping. 51.1. Har qanday uchtasi bir to’g’ri chiziqda yotmaydigan 6 ta nuqta berilgan. Shu 6 ta nuqtalar orqali nechta turlicha chiziq o’tkazish mumkin? tải về 404.35 Kb. Chia sẻ với bạn bè của bạn:
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